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Solve the following system of linear equations in three variables. x + y + z = 6; 2x + 3y + 4z = 20; 3x + 2y + 5z = 22

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Solve the following system of linear equations in three variables. x + y + z = 6; 2x + 3y + 4z = 20; 3x + 2y + 5z = 22

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x + y + z = 6 … (1)

2x + 3y + 4z = 20 … (2)

3x + 2y + 5z = 22 … (3)

Sub. z = 3 in (5) ⇒ y – 2(3) = -4

y = 2

Sub. y = 2, z = 3 in (1), we get

x + 2 + 3 = 6

x = 1

x = 1, y = 2, z = 3

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