(i) α + 2, β + 2 are the roots (given)
Sum of the roots = α + 2 + β + 2
= α + β + 4
= 2 + 4 = 6
Product of the roots = (α + 2) (β + 2)
= αβ + 2α + 2β + 4
= αβ + 2(α + β) + 4
= 3 + 2 x 2 + 4
= 3 + 4 + 4 = 11
∴ The required equation = x2 – 6x + 11 = 0.
(ii) (α - 1)/(α + 1), (β - 1)/(β + 1)

⇒ 3x2 – 2x + 1 = 0