Object distance u = 10 cm
Focal length of a concave lens f= -15 cm
Let v be the image distance,

Distance of image v = 6 cm
Magnification m =\(\frac{v}{u}\) =\(\frac{6}{10}\) = 0.6
And Magnification m =\(\frac{h'}{h}\)
Where h’ – height of image
h – height of object
0.6 = \(\frac{h'}{3}\)
∴ h’ = 3 × 0.6 = 1.8 cm
∴ Height of image = 1.8 cm