Sn = 3n2 + 5n
Taking n = 1, we get
S1 = 3(1)2 + 5(1)
⇒ S1 = 3 + 5
⇒ S1 = 8
⇒ a1 = 8
Taking n = 2, we get
S2 = 3(2)2 + 5(2)
⇒ S2 = 12 + 10
⇒ S2 = 22
∴ a2 = S2 – S1 = 22 – 8 = 14
Taking n = 3, we get
S3 = 3(3)2 + 5(3)
⇒ S3 = 27 + 15
⇒ S3 = 42
∴ a3 = S3 – S2 = 42 – 22 = 20
So, a = 8,
d = a2 – a1 = 14 – 8 = 6
Now, we have to find the 15th term
an = a + (n – 1)d
a16 = 8 + (16 – 1)6
a16 = 8 + 15 × 6
a16 = 8 + 90
a16 = 98
Hence, the 16th term is 98.