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Construct a ΔPQR which the base PQ = 4.5 cm, ∠R = 35° and the median from R to RG is 6 cm.

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Construction:

Step (1) Draw a line segment PQ = 4.5 cm

Step (2) At P, draw PE such that ∠QPE = 35°.

Step (3) At P, draw PF such that ∠EPF = 90°.

Step (4) Draw ⊥r bisector to PQ which intersects PF at O.

Step (5) With O centre OP as raidus draw a circle.

Step (6) From G mark arcs of 6 cm on the circle.

Mark them as R and S.

Step (7) Join PR and RQ.

Step (8) PQR is the required triangle.

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