![](https://www.sarthaks.com/?qa=blob&qa_blobid=16121560453384263113)
Construction:
Step (1) Draw \(\overline{AB}\) = 5.5 cm
Step (2) Draw ∠BAE = 25°
Step (3) Draw ∠FAE = 90°
Step (4) Draw ⊥r bisector to AB.
Step (5) The ⊥r bisector meets AF at O.
Step (6) Draw a circle with O as centre and OA as radius.
Step (7) Mark an arc of length 4 cm from G on the ⊥r bisector and name as N.
Step (8) Draw CC1 || AB through N.
Step (9) Join AC & BC.
Step (10) ΔABC is the required triangle.