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Construct a ΔABC such that AB = 5.5 cm, C = 25° and the altitude from C to AB is 4 cm.

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Construction:

Step (1) Draw \(\overline{AB}\) = 5.5 cm

Step (2) Draw ∠BAE = 25°

Step (3) Draw ∠FAE = 90°

Step (4) Draw ⊥r bisector to AB.

Step (5) The ⊥r bisector meets AF at O.

Step (6) Draw a circle with O as centre and OA as radius.

Step (7) Mark an arc of length 4 cm from G on the ⊥r bisector and name as N.

Step (8) Draw CC1 || AB through N.

Step (9) Join AC & BC.

Step (10) ΔABC is the required triangle.

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