Question

Three resistances are connected in an electrical circuit as shown in the circuit diagram. Determine the potential difference across resistance R₂ .

Answer 1

For series connection, the effective resistance

R_S = R₁ + R₂ + R₃ 

= 1 + 2 + 3 = 6Ω

Total potential = 12V 

Amount of current flowing through the circuit

I =\(\frac{V}{R_S} = \frac{12V}{6Ω}\)= 2A

Potential difference across resistance R₂

V = I × R₂ 

= 2 × 2 = 4V 

The potential difference across the resistance R₂ = 4 V