Since the wire is bend in form of the square and we know that sides of square are equal so each side will have same resistance i.e 5 ohm. Now if we make diagonal two faces in each side of the diagonal will have two sides and resistance will be 10 ohm. As shown below.
So total resistance will be \(\frac{1}{R_{eq}} =\frac1{10}+\frac1{10}=\frac2{10}\)
⇒ Req = 5 ohm
Hence equivalent resistance is 5 ohm.
