Question

Calculate the pressure exerted by a column of water of height 0.85 m (density of water, p_w =1000 kg m^-3) and kerosene of same height (density of kerosene, p_k = 800 kg m^-3)

Answer 1

Pressure due to water = hp_wg = 0.85 m × 1000 kg m^-3 × 10 ms^-2 = 8500 Pa. 

Pressure due to kerosene = hp_k g = 0.85 m × 800 kg m^-3 × 10 ms^-2 = 6800 Pa.