Question

What is the rise in temperature of 5 kg of water if it is given 84,000 J heat energy? Specific heat capacity of water 4200 J Kg^-1°C^-1.

Answer 1

Given, m = 5 kg 

Q = 84,000 J 

C = 4200 J Kg^-1 °C^-1 

Let rise in the temperature be ∆T. 

Heat energy (Q) = mC∆T 

84,000 = 5 x 4200 x ∆T 

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= 4°C