Question

A food chain consists of the following members. If the last member receives 30 J of energy, make a diagrammatic representation to show the flow of energy. 

Snake, Vulture, Plants and Rat.

Answer 1

Plants (30000 J) → Rat(3000 J) → Snake (300 J) → Vulture (30 J) 

According to 10% Law 

The 10% of the energy present in snakes is passed to the vultures.

Therefore, energy present in snakes =  30 x  \((\frac{100}{10})\) = 300 J

Similarly, energy present in rats = 300 x \((\frac{100}{10})\) = 3000 J

and the energy present in plants = 3000 x \((\frac{100}{10})\) = 30000 J