Answer: (b) = 1.13 m3
The volume of water left in the cylinder = Volume of water filled in the right circular cylinder – Volume of the solid
= Vol. of the right circular cylinder – (Vol. of cone + Vol. of the hemisphere)
= \(\frac{22}{7} \times 0.6 \times 0.6 \times 1.8 \, -\, \big(\frac{1}{3} \times \frac{22}{7} \times (0.6)^2 \times 1.2 + \frac{2}{3} \times \frac{22}{7} \times (0.6)^3 \big)\)
= 2.03 - (0.45 + 0.45)
= 2.03 - 0.90
= 1.13 m3