Answer : (d) (1, \(\frac{3}{2}\))
Given f (x) = \(exp(\sqrt{5x-3-2x^2}) = exp(\sqrt {-(2x^2-5x+3)})\)
For f (x) to be defined
– (2x2 – 5x + 3) ≥ 0
⇒ 2x2 – 5x + 3 ≤ 0
⇒ 2x2 – 3x – 2x + 3 ≤ 0
⇒ (2x – 3) (x – 1) ≤ 0 ( ∵ (x-a) (x-b) ≤ 0 ⇒ a ≤ x ≤ b where a < b)
⇒ \(x\leq \frac{3}{2}\) and x ≥ 1
⇒ 1 ≤ x ≤ \(\frac{3}{2}\)