Answer : (b) (2π – 4) cm2

From the three figures, we can see that,
Area of shaded region = Area of the square – (Total area shown by region a + Total area shown by region b)
The total area of the region a = Area of the square – area of the inscribed circle

Total area of region b = Area of square – 4(Area of a quadrant)
= 4 - 4\(\big(\frac{1}{4} \pi \times (1)^2\big) \) = (4 - π)
∴ Required area = 4 – (4 – π + 4 – π)
= (2π – 4) cm2.