Question

A solid is in the form of a right circular cone mounted on a hemisphere. The radius of the hemisphere is 2.1 cm, and the height of the cone is 4 cm. The solid is place in a cylindrical tub full of water in such a way that the whole solid is submerged in water left in the tub.

Answer 1

Original volume of water in the cylindrical tub

= Volume of Cylinder

= πr²h

= 22/7 x 5² x 9.8

= 22×25×1.4

= 770cm³

Given that Radius of hemisphere, R = 2.1cm

and height of cone, h = 4cm

Volume of a solid = Volume of cone + Volume of hemisphere

= 37.884cm³

∴ Volume of water displaced (removed) = 37.884cm³

Hence, the required volume of the water left in the cylindrical tub = 770 – 37.884

= 732.116 cm³