Question

The diagonals of a rhombus are 24 cm and 10 cm. What is the perimeter of the rhombus ?

Answer 1

Each side = \(\sqrt{(\frac{24}{2})^2+(\frac{10}{2})^2}\) = \(\sqrt{144+25}\) = \(\sqrt{169}\) 13 cm

∴ Perimeter = 4 × 13 cm = 52 cm