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in Matrices and Determinants by (47.6k points)
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If \( \begin{vmatrix} 4&3\\3&1 \end{vmatrix}\) = -5 then the value of \( \begin{vmatrix} 20&15\\15&5 \end{vmatrix}\) is: 

(a) -5 

(b) -125 

(c) -25 

(4) 0

1 Answer

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Best answer

(b) -125

\( \begin{vmatrix} 20&15\\15&5 \end{vmatrix}\)

= 5 x 5 \( \begin{vmatrix} 4&3\\3&1 \end{vmatrix}\)

= 5 x 5 x (-5) 

= -125

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