(d) several solutions
Check for \(\frac{a_1}{a_2}\)\(\ne\)\(\frac{b_1}{b_2}\), \(\frac{a_1}{a_2}\)= \(\frac{b_1}{b_2}\)\(\ne\)\(\frac{c_1}{c_2}\)
and \(\frac{a_1}{a_2}\)= \(\frac{b_1}{b_2}\)=\(\frac{c_1}{c_2}\)
Here a1 =2, b1 =3,c1= -5
a2 = 4, b2 = 6, c2 = –10.