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The simultaneous equatoins 2x + 3y = 5, 4x + 6y = 10 have : 

(a) no solution 

(b) only one solution 

(c) only two solutions 

(d) several solutions

1 Answer

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Best answer

(d) several solutions

Check for \(\frac{a_1}{a_2}\)\(\ne\)\(\frac{b_1}{b_2}\)\(\frac{a_1}{a_2}\)\(\frac{b_1}{b_2}\)\(\ne\)\(\frac{c_1}{c_2}\)

and \(\frac{a_1}{a_2}\)\(\frac{b_1}{b_2}\)=\(\frac{c_1}{c_2}\)

Here a1 =2, b1 =3,c1= -5

a2 = 4, b2 = 6, c2 = –10.

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