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If \(a^2+\frac{1}{a^2} = 10,\) then the value of \(a^4+\frac{1}{a^4} \) is

(a) 90 

(b) 98 

(c) 100 

(d) 102

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(b) 98

\(a^2+\frac{1}{a^2} = 10\) ⇒ \(\bigg(a^2+\frac{1}{a^2}\bigg)^2 = 10^2\)

⇒ \(a^4+2+\frac{1}{a^4} = 100\) ⇒ \(a^4+\frac{1}{a^4} = 98.\)

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