(i) Let f(x) = x2 then f(x + h) = (x + h)2
Now \(\frac{d}{dx}\)f(x)
Thus \(\frac{d}{dx}\)(x2) = 2x
(ii) Let f(x) = e-x then f(x + h) = e-(x + h)
Now \(\frac{d}{dx}\)f(x)
(iii) Let f(x) = log(x + 1)
Then f(x + h) = log(x + h + 1) = log((x + 1) + h)
Now \(\frac{d}{dx}\)f(x)