Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.8k views
in Algebra by (44.5k points)
closed by

Expand using appropriate identities:

(2m + n)(2m +p)

1 Answer

+1 vote
by (55.5k points)
selected by
 
Best answer

(2m + n) (2m + p)

Comparing (2m + n) (2m + p) with (x + a) (x + b) we have x = 2n; a = n ;b = p

(x – a)(x + b) = x2 + (a + b)x + ab

(2m +n) (2m +p) 

= (2m2) + (n +p)(2m) + (n) (p)

= 22m2 + n(2m) + p(2m) + np

= 4m2 + 2mn + 2mp + np

Related questions

0 votes
1 answer
0 votes
1 answer
0 votes
1 answer
0 votes
1 answer
asked Nov 19, 2020 in Algebra by Ishti (44.5k points)
0 votes
1 answer

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...