Let S = {1, 2, 3,…, 10}, n(S) = 10
Let A be the event of drawing a number greater than 4.
Then A= {5, 6, 7, 8, 9, 10}, n(A) = 6
∴ P(A) = \(\frac{n(A)}{n(S)}=\frac{6}{10}\)
Let B be the event of getting a even number.
Then B = {2, 4, 6, 8, 10}
Now A ∩ B = {6, 8, 10}, n(A ∩ B) = 3
P(A ∩ B) = \(\frac{3}{10}\)
We have to find P (\(\frac{B}{A}\))
