Number of students = 1000 i.e., n(S) = 1000
Let A be the event of selecting a girl student from class XI.
Let B be the event of selecting a girl student
Number of girls = 450; n(B) = 450
∴ P(B) = \(\frac{n(B)}{n(S)}=\frac{450}{1000}\)
Number of girls studying in XI is 20% of 450 = \(\frac{20}{100}\) x 450
= 90
i.e., n(A ∩ B) = 90
∴ P(A ∩ B) = \(\frac{n(A∩B)}{n(S)}=\frac{90}{1000}\)
We have to find P(\(\frac{A}{B}\))
