x2 - 8x + 15 = x2 - 5x - 3x + 15
= x(x - 5) - 3(x - 5) = (x - 5)(x - 3)
x2 - 25 = (x - 5)(x - 5)
∴ \(\frac{1}{x^2-8x+15}-\frac{1}{x^2-25}\) = \(\frac{1}{(x-5)(x-3)}\) - \(\frac{1}{(x-5)(x-5)}\)
= \(\frac{(x-5)-(x-3)}{(x-3)(x-5)(x-5)}\) (Note the step)
= \(\frac{x-5-x+3}{(x-3)(x-5)(x-5)}\) = \(\frac{-2}{(x-3)(x-5)(x-5)}\)