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20 persons were invited for a party. In how many ways can they and the host be seated around a circular table? In how many of these ways will two particular persons be seated on either side of the host?

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There is 1 host and 20 guests, they are to be seated around a circular table. 

(i) Let us fix the seat of one person, say the host, the 20 guests will be seated around the circular table in 20 ! ways, [or, (n – 1)! = (21 – 1) ! = 20!] 

(ii) The two particular persons can be seated on either side of the host in 2 ways and for each way of their taking seats, the remaining 18 persons can be seated around the circular table in 18 ! ways 

Hence the number of ways of seating two particular persons on either side of the host = 2 × 18 !. [or, 2! × (19 – 1)!, considering the host and two particular persons as one entity.]

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