Diamter of the circular garden d = 49 m
Radius r = \(\frac{d}{2}\)
= \(\frac{49}{2}\) m
Area of the circular garden = πr2 sq units
= \(\frac{22}{7}\) x \(\frac{49}{2}\) x \(\frac{49}{2}\) m2
= 1,886.5 m2
Cost of levelling a m2 area = Rs 150
∴ Cost of levelling 1886.5 m2 = Rs 150 x 1886.5
= Rs 2,82,975
Cost of levelling the flower garden = Rs 2,82,975