Outer circumference of the circular lawn = 88 cm
2πR = 88 cm
Inner circumference of the lawn 2πr = 44 cm
2πR – 2πr = 88 – 44
2 x \(\frac{22}{7}\) (R – r) = 44
(R – r) = \(\frac{44\times7}{2\times22}\)
Outer radius – Inner radius = 7 cm
∴ Width of the lawn = 7 cm
Also 2πR + 2πr = 88 + 44
2π(R + r) = 132
π(R + r) = \(\frac{132}{2}\)
= 66 cm
Area of the path = πR2 – πr2 sq. units
= π(R + r) (R – r)
= 66 x 7 cm2
Area of the path = 462 cm2