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+1 vote
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in Physics by (34.7k points)

Two blocks (m = 0.5 kg and M = 4.5 kg) are arranged on a horizontal frictionless table as shown in figure. The coefficient of static friction between the two blocks is \(\frac 37\) .Then the maximum horizontal force that can be applied on the larger block so that the blocks move together is .......N. (Round off to the Nearest Integer) [Take g as 9.8 ms–2]

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2 Answers

+2 votes
by (35.1k points)

Answer is 21

= 21  Newton

0 votes
by (40 points)

Answer is 21

= 21  Newton

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