Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
328 views
in Trigonometry by (25.8k points)
closed by

Find the principal value of each of the following :

\(\sec^{-1}\left(\frac{-2}{\sqrt{3}}\right)\)

1 Answer

+1 vote
by (27.7k points)
selected by
 
Best answer

\(\sec^{-1}\left(\frac{-2}{\sqrt{3}}\right)\)\(=\pi-\sec^{-1}\left(\frac{2}{\sqrt{3}}\right)\)

[ Formula: sec -1(-x)= π – sec -1(x) ]

\(=\pi-\frac{\pi}{6}=\frac{5\pi}{6}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...