Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
526 views
in Trigonometry by (27.7k points)
closed by

The principal value of \(cosec^{-1}(\sqrt{2})\)is

A. \(\frac{-\pi}{4}\)

B. \(\frac{3\pi}{4}\) 

C. \(\frac{5\pi}{4}\) 

D. none of these

1 Answer

+1 vote
by (25.8k points)
selected by
 
Best answer

Correct Answer is \(-\frac{\pi}{4}\)

Let the principle value be given by x 

Now, let x = \(cosec^{-1}(\sqrt{2})\)

cosec x = \(-\sqrt{2}\)

cosec x= - cosec( \(\frac{\pi}{4}\)) (\(\because cosec\left(\frac{\pi}{4}\right)=\sqrt{2}\)

cosec x=cosec( \(-\frac{\pi}{4}\)) ( \(\because -cosec(\theta)=cosec(-\theta\))) 

x =\(-\frac{\pi}{4}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...