Let x and y be number of kilograms of bran and rice.
∴According to the question,
80x + 100y ≥ 88, 40x + 30y ≥ 36, x ≥ 0, y ≥ 0
Minimize Z = 5x + 4y
The feasible region determined 80x + 100y ≥ 88, 40x + 30y ≥ 36, x ≥ 0, y ≥ 0 is given by

The feasible region is unbounded. The corner points of feasible region are A(0,1.2) , B(0.6,0.4) , C(1.1,0).
The value of Z at corner points are
Corner Point |
Z = 5x + 4y |
|
A(0, 1, 2) |
4.8 |
|
B(0, 6, 0.4) |
4.6 |
Minimum |
C(1.1, 0) |
5.5 |
|
The minimum value of Z is 4.6 at point (0.6,0.4).
Hence, the diet should contain 0.6 kgs of bran and 0.4 kgs of rice for achieving minimum cost of Rs.4.6.