Let x kg of bran and y kg of rice be contained in a cereal.
∴ Minimize, z = 28x + 25y
Subject to constraints

x ≥ 0, y ≥ 0
First we draw the line AB and CD whose equation are 20x + 25y = 22 and 20x + 15 y = 18 respectively.
Now,


The feasible region is XBPCY which is shaded in the figure.
The vertices of the feasible region are B (1.1, 0), P and C (0, 1.2). P is the point of intersection of the lines 20x + 25y = 22 and 20x + 15y= 18. Solving those we get the point P (0.6,0.4)
The minimum value of z is :

Hence, the minimum value of z is 26.8 at the point P(0.6, 0.4)