Question

If the diagonals of a rhombus are 12 cm and 16 cm, find the length of each side.

Answer 1

We know in rhombus diagonals bisect each other at right angle.

In ΔAOB

AO = \(\frac{12}{2}\) = 6 cm , BO = \(\frac{16}{2}\) = 8 cm

Using pythagoras theorem in ΔAOB

AB² = AO² + BO²

AB² = 6² + 8²

AB² = 36 + 64

AB² = 100

AB = \(\sqrt{100}\) = 10 cm

Therefore each side of a rhombus is 10 cm.