Option : (B)
Given,
ABCD is a rhombus

AC = 24 cm,
BD = 18 cm
= AB=BC=CD=DA
[side of rhombus]
We know that diagonals of rhombus bisect each other at 90°
In right ∆ AOB,
AB2 = BO2 + AO2
AB2 = 122 + 92
= 144 + 81
= 225
AB = \(\sqrt{225}\) = 15 cm
Side of rhombus = 15 cm