Given,
Volume of each cube = 512 cm3
Let length of edge of each cube = a cm
So,
= a3 = 512
= a = \(\sqrt[3]{512}\) = 8 cm
When these two cubes are joined end to end a cuboid is formed:
Length of cuboid = 8 + 8 = 16 cm
Breadth = 8 cm
Height = 8 cm
Surface area of resulting cuboid = 2(lb x bh x lh) = 2(16 x 8 + 8 x 8 + 8 x 16)
= 2(128 + 64 + 128) = 2 x 320 = 640 cm2