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If the length of a median of an equilateral triangle is x cm, then its area is

A. x2 

B.\(\frac{\sqrt{3}}{2}\) x2 

C. \(\frac{{x}^2}{\sqrt{3}}\)

D.\(\frac{{x}^2}{2}\)

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Best answer

Median of an equilateral = x cm

In an equilateral triangle median is an altitude.

Let the side of triangle be a cm

(AB)2 = (AD)2 + (BD)2

(a)2 = (x)\((\frac{a}{2})^2\) c

a = \(\frac{2x}{\sqrt{3}}\) cm

Area of an equilateral triangle = \(\frac{\sqrt3a^2}{4}\) = \(\frac{\sqrt{3}\times{2x}\times{2x}}{{4}\times\sqrt{3}\times\sqrt{3}}\) = \(\frac{\sqrt3a^2}{3}\) 

\(\frac{\sqrt{3}\times\sqrt{3x}^2}{{3}\times\sqrt{3}}\) = \(\frac{x^2}{\sqrt{3}}\) cm2

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