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Evaluate : \(\int\)\(\frac{1}{1+cos3x}\)dx

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Best answer

Let I =\(\int\)\(\frac{1}{1+cos3x}\)dx

\(\int\)\(\frac{1}{1+cos3x}\)dx

Now,

Multiply with Conjugate,

Hence,

 I =\(\)\(\frac{1-cos3x}{3sin3x}\) + C

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