Given radius of cylinder (r’) = \(\frac{12}2\) = 6 cm
Given radius of hemisphere (r’’) = \(\frac{6}2\) = 3 cm
Given height of cylinder (h) = 15 cm
Height of cone (l) = 12 cm
Volume of cylinder = πr2h
= πr(6)2(15) cm ………. (1)
Volume of each cone = Volume of cone + Volume of hemisphere
V = π(r)2(l) + \(\frac{2}3\) π(r)3
V = π(3)2(12) + \(\frac{2}3\) π(3)3 ………… (2)
Let number of cone be n
n (volume of each cone) = volume of cylinder
n = [( \(\frac{1}3\) π(3)2 (12) + \(\frac{2}3\) π(3)3] = π(16)2 15
⇒ n = 10
