Question

The density of a gas is found to be 5.46 g/dm³ at 27°C and under 2 bar pressure. What will be its density at STP.

Answer 1

d₁ = \(\frac{p_1M}{RT_1}\) 

d₂ = \(\frac{p_2M}{RT_2}\) 

\(\frac{d_1}{d_2}\) = \(\frac{p_1T_2}{p_2T_1}\) 

Thus, d₂ = \(\frac{d_1T_1p_2}{T_2p_1}\) 

Substituting the value we have,

d₂ = \(\frac{5.46\ g\ dm^{-3}\times300.15\ K\times1\ bar}{2\ bar\times273.15\ K}\) 

= 2.99gdm^-3.