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Evaluate the following integral : ∫ x/((x+1)(x2+1))dx

\(\int\frac{x}{(x+1)(x^2+1)}\)dx

1 Answer

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Best answer

I =  ∫ x/((x+1)(x2+1))dx

x = A(x2 + 1) + (Bx + C)(x + 1) 

Equating constants,

0 = A + C 

Equating coefficients of x,

1 = B + C 

Equating coefficients of x2

0 = A + B 

Solving, we get

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