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Evaluate the following integral : ∫1/(1+x+x2+x3)dx

\(\int\frac{1}{1+x+x^2+x^3}\)dx

1 Answer

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Best answer

I = ∫1/(1+x+x2+x3)

1 = (Ax + B)(x + 1) + C(x2 + 1) 

Equating constants,

1 = B + C 

Equating coefficients of x,

0 = A + B 

Equating coefficients of x2,

0 = A + C 

Solving, we get

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