Let the angles of the triangle be (a – d)°, a° and (a + d)°.
We know that the sum of the angles of a triangle is 180°.
⇒ a – d + a + a + d = 180°
⇒ 3a = 180°
∴ a = 60°
Given \(\frac{number\,of\,degrees\,in\,the\,least\,angle}{number\,of\,degrees\,in\,the\,mea\,angle}\) = \(\frac1{120}\)
⇒ 120 – 2d = 1
⇒ 2d = 119
∴ d = 59.5
Hence, angles are:
⇒ (a – d) ° = 60° – 59.5° = 0.5°
⇒ a° = 60°
⇒ (a + d) ° = 60° + 59.5° = 119.5°
∴ Angles of triangle in radians:
