Question

In a full wave junction diode rectifier, the input ac voltage has rms value of 10V. The transformer used is a step up one having transformation ratio 1:2. Calculate the DC voltage in the rectified output.

Answer 1

Here,

Input rms voltage, 

V_rms = 10 V 

∴ Peak value of input voltage, 

E₀ = √2. 

V_rms = √2 ×10 

= 14.14 V 

Since, the transformer is a step-up transformer, having transformation ratio 1:2, the maximum value of output voltage of the transformer applied to the diodes will be : 

E'₀ = 2 × E₀ 

= 2 × 14.14 

= 28.28 V

∴ DC voltage = \(\frac{2E'_0}{\pi}\) 

= \(\frac{2\times 28.28\times 7}{22}\) 

= 18 V.