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If = \(\begin{bmatrix} 2&3 \\ 1& 2 \end{bmatrix}\) and f(x) = x2 - 4x + 1, find f(A).

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 we have A = \(\begin{bmatrix} 2&3 \\ 1& 2 \end{bmatrix}\) and f(x) = x2 - 4x + 1.

Therefore, f(A) = A2 − 4A + I , where = \(\begin{bmatrix} 1&0 \\ 0& 1 \end{bmatrix}\) is an identity matrix of order 2.

Hence, f(A) = 0, where 0 is zero matrix of order 2.

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