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Solve the following linear inequations in R

 – 4x > 30, when 

i. x ∈ R 

ii. x ∈ Z 

iii. x ∈ N

1 Answer

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Best answer

Given,

–4x > 30

⇒ \(-\frac{4x}{4}\) > \(\frac{30}{4}\)

⇒ - x > \(\frac{15}{2}\)

∴ x < \(-\frac{15}{2}\) 

i. x ∈ R

When x is a real number, the solution of the given inequation is (-∞,\(-\frac{15}{2}\)).

ii. x ∈ Z

As - 8 < \(-\frac{15}{2}\) < -7,

When x is an integer, the maximum possible value of x is –8.

Thus,

The solution of the given inequation is {…, –11, –10, –9, –8}.

iii. x ∈ N 

As natural numbers start from 1 and can never be negative, when x is a natural number, the solution of the given inequation is ∅.

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