Question

Construct a quadrilateral ABCD in which AB=3.5cm, BC=5cm, CD=4.6cm, ∠B = 125° and ∠C = 60°.

Answer 1

Given :

AB = 3.5 cm , BC = 5 cm , CD = 4.6 cm , \(\angle B\) = \(125^\circ,\) \(\angle C=60^\circ\)

Construction :

Step 1 : Draw segment AB of length 3.5 cm.

Step 2 : Draw angle B of 125 degrees.

Step 3 : Taking B as centre draw arc of radius 5 cm which cuts the segment BP. Point of intersection is C.

Step 4 : Draw angle C of 60 degrees.

Step 5 : Taking C as centre draw arc of radius 4.6 cm which cuts the segment CG. Point of intersection is D.

Step 6 : Join AD.

ABCD is the required quadrilateral.