Given
√3x2 + 10x - 8√3 = 0
On comparing it with ax2 + bx + x = 0, we get
a = √3, b = 10 and c = -8√3
Discriminant D is given by:
D = (b2 - 4ac)
= (10)2 - 4 x √3 x (-8√3)
= 100 + 96
= 196 > 0
Hence, the roots of the equation are real.
Roots α and β are given by:
Thus, the roots of the equation are \(\frac{2\sqrt3}3\) and \(-4\sqrt3\)