Question

Find the roots of the following equations, if they exist, by applying the quadratic formula:

√3x² - 2√2x - 2√3 = 0

Answer 1

The given equations is √3x² - 2√2x - 2√3 = 0

Comparing it with ax² +bx + c = 0. we get

a = √3, b = -2√2 and c = -2√3

∴ Discriminant, D = b² - 4ac = (-2√2)² - 4 x √3 x (-2√3) = 8 + 24 = 32 > 0

So, the given equation has real roots.

Now. √D = \(\sqrt{32}\) = 4√2

Hence,√6 and - √6/3 are the root of the given equation.