The given equations is 4√3x2 + 5x - 2√3 = 0
Comparing it with ax2 +bx + c = 0.we get
a = 4√3, b = 5 and c = - 2√3
∴ Discriminant, D = b2 - 4ac = 52 - 4 x 4√3 x (-2√3) = 25 + 96 = 121 > 0
So, the given equation has real roots
Now, √D = \(\sqrt{121}\) = 11

Hence √3/4 and - 2√3/3 are the root of the given equation.