Question

Construct a △PQR, in which PQ = 6 cm, QR = 7 cm and PR = -8 cm. Then, construct another triangle whose sides are 4/5 times the corresponding sides of △PQR

Answer 1

Steps of Construction

Step 1: Draw a line segment QR = 7 cm.

Step 2: With Q as center and radius 6 cm, draw an arc.

Step 3: With R as center and radius 8cm, draw an arc cutting the previous arc at P

Step 4: Join PQ and PR. Thus, △PQR is the required triangle.

Step 5: Below QR, draw an acute angle ∠RQX.

Step 6: Along OX, mark five points R₁,R₂,R₃,R₄ and R₅ such that

QR₁ = R₁R₂ = R₂R₃ = R₃R₄ = R₄R₅.

Step 7: Join RR₅.

Step 8: From R₄, draw R₄R' || RR₅ meeting QR at R'.

Step 9: From R’, draw P R PR ’ ’|| meeting PQ in P’.

Here, △P'QR' is the required triangle, each of whose sides are \(\frac{4}{5}\)times the corresponding sides of △PQR.